As shown in the figure, two equal masses hang | vedclass

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(B) When the mass on the right is given a horizontal velocity $u$, it starts moving in a circular arc (pendulum motion) because it is constrained by t

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the mass on the right will be nearer to the ground

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(B) When the mass on the right is given a horizontal velocity $u$, it starts moving in a circular arc (pendulum motion) because it is constrained by the string connected to the pulley.As it moves in a circular arc, it gains a centripetal acceleration directed towards the center of the pulley.For the mass on the right, the equation of motion along the radial direction is $T - mg \cos 	heta = \frac{mu^2}{R}$, where $T$ is the tension, $m$ is the mass, $g$ is acceleration due to gravity, $	heta$ is the angle with the vertical, and $R$ is the length of the string.This implies $T = mg \cos 	heta + \frac{mu^2}{R}$.Since the tension $T$ in the string is greater than the weight $mg$ of the mass on the left (because $T > mg \cos 	heta$ and the mass on the right is moving), the mass on the left will be pulled upwards.Therefore, the mass on the left will rise, making it farther from the ground, while the mass on the right will be nearer to the ground.

As shown in the figure, two equal masses hang on either side of a pulley at the same height from the ground. The mass on the right is given a horizontal speed $u$. After some time :-

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